Math, asked by rnpatelpatel, 3 months ago

(-3
For
a group of 500 students data relating to
manke un Statistics and bussiness administration amo
given below : -
statistics
Business Administreation
Go
Moan
+2
Standard deviation
12
Sum
of product of
of deviation about actual mean a 61440
And & W Coefficient of
correlation​

Answers

Answered by Rameshjangid
0

Answer:

The median is irrelevant.

First compute

Mean = Sum/n = 500/50 = 10

Mean SSQ = SSQ/n = 6000/50 = 120

Now,

Var = (Mean SSQ) - (Mean)^2

SD = \sqrt{(Var)}

You can finish the computations from here.

UPDATE

The procedures above are the Maximum Likelihood Estimates (MLE’s) of the Mean and SD. Usually, the sample variance is computed by dividing the mean centered sum of squared deviations by n-1. To make the adjustment, compute the Mean as above. Then, define

Var* = [n/(n-1)] Var

SD* = \sqrt{(Var*)}

Using the numbers above, the MLE of the SD is

Var = 120 - (10)^2 = 120 - 100 = 20

SD =\sqrt{20} = 4.47

Step-by-step explanation:

Median value is unnecessary

Sum of 50 observations is 500

Mean of of 50 observations =500/50 =10

Sum of of the sqares =6000

Variance =( (6000)/50 ) —(10)^2

=120-100=20

Sd=(20)^1/2 =4.5

Second formula Bassells for correct value

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