Question

3. For the arrangement shown below, find the
magnitude and direction of the net gravitational
force acting on the central particle at 0, with respect
to the axes shown is
2 Mo-
M
O
-----O4 M
7 M9
1
1
YA
05M
d
Me X 63M
1
5 Mó
07M
d
1
1
4 MO
d/2
--
-------03M
M
d
d​

Answer 1

Answer:

It's a easy question , just eliminate those pair of masses which are opposite according to the centre mass, like for the the 5m at the right with the centre mass m is opposite to the the 5m mass and centre mass at the left side....

Explanation:

because of this elimination most of the mass cancel each other effect at last

top left 2m mass ,

down right 3m mass and

centre right 3m mass are left ...

now apply Newton's gravitational law

F= (Gm1m2)/r²

dist between 2m and centre m or 3m and centre mass m is ✓2d (apply geometry and Pythagoras)

(do further calculations please)

by solving the underroot given in photo ull get the answer.....