3 g of magnesium can react completely with 4 g of sulphur to form 7 g of magnesium sulphide.
Calculate the mass of magnesium required when 12 g of sulphur is given. Also calculate the mass of
magnesium sulphide formed.
Give a proper answer+With explanation.
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Answer:
Atomic mass of Mg = 24 g
Atmic mass of S = 32 g
Ratio of Mg and S in MgS = 24:32 = 3:4
Mass ratio / Atomic mass of Mg = 3/24 = 1/8
Mass ratio / atomic mass of S = 4/32 = 1/8
Hence, the ratio of atoms in MgS is = (1/8) : (1/8) = 1:1
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