(3) Ga
7.
When So, is passed in acidified K_Cr,O, solution oxidation state of S changed from
(1) +4 to 0
(2) +4 to +2
(4) +6 to +4
(3) +4 to +6
Answers
Answered by
1
Answer:
The reaction of sulphur dioxide with acidified K
2
Cr
2
O
7
in acidic medium is
3SO
2
+Cr
2
O
7
2−
+2H
+
→3SO
4
2−
+2Cr
3+
+H
2
O
So Oxidation state of Sulphur in SO
2
is +4 which is changed to +6 in SO
4
2−
.
Hence option C is correct.
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