3 grams of carbon is completly burnt in large excess of oxygen,the weight of carbondioxide is
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ANSWER: ❷⓪⓪m
ⒺⓍⓅⓁⒶNⒶⓉⒾⓄⓃ
\huge\text{\underline{\underline{GIVEN}}}
GIVEN
Initial Velocity of the car \red{\boxed{\mathfrak{ (u) = 0 ms^{-1} }}}
(u)=0ms
−1
Acceleration of the car \red{\boxed{\mathfrak{ (a) = 4 ms^{-2} }}}
(a)=4ms
−2
TIME TAKEN \red{\boxed{\mathfrak{ (t) = 10s}}}
(t)=10s
WE HAVE TO FIND \red{\boxed{\mathtt{DISTANCE (s)}}}
DISTANCE(s)
\huge\text{\underline{\underline{SOLUTION}}}
SOLUTION
To find the distance let's use the 2nd equation of motion
WHICH IS \red{\boxed{\mathfrak{ s = ut + \frac{1}{2}at^2}}}
s=ut+
2
1
at
2
NOW PUTTING THE VALUES
\huge{\red{\boxed{\mathfrak{ \implies s = 200 m}}}}
⟹s=200m
∴The CAR will cover 200 m distance after 10 s.
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