Question

3 grams of h2 react with 2 grams of o2 to yield water (a) which is the limiting reagent (2) calculate the maximum amount of water that can be formed (3) calculate the amount of one of the rectants which remains unrected

Answer 1

H2-----> moles =wt/mwt
3/18=0.165moles
same for o2--> 2/32=0.625moles

eq is. 2H2 + O2 -----> 2H2O

theoretically-: 2. 1. 2. (moles)
exp. -: 0.165 0.625 x (moles)

hydrogen is the limiting reagent (cause in one mole of oxygen we are getting 0.625 th so in 2 moles it should be 1.25 ..but it is 0.165 )

so X = 0.165
masd of h2o = 0.165(moles) x 18(mwt) =