3 grooves AB, AC and AD are made in a circular disk lying in a vertical
ane 3 particles B, C and D constrained to move along path AB. AC and
respectively are released from point A Particle B reaches points
me to particle C reaches point
in time to. Then which of the following is incorrect(s).
in time to and particle Dreaches at point
(A) te = tc to
(B) lg>100
(D) 10 = lg>to
(C) tc > tb > to
Answers
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Answer:
A) te = tc to
Explanation:
Three grooves = AB, AC and AD
Three particles = B, C and D
Relative velocity of one particle = v- v cos 60
Length of one side = L
Thus, s=1/2at² or t = (2s/a)^(1/2)
When the relative velocity of a particle will be calculated with respect to another particle along the same line, then the particles will never have an equal velocity. Thus, the time taken by the particles will be different and not same. Therefore, all the particles will reach at different time interval. So te = tc to is incorrect.
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