Question

3 horses cost is equal to 5 cows cost. 4 horses, 6 Cows total cost is 1900/- then what is the cost of each horse?

Answer 1

Answer:

Step-by-step explanation:

250

Answer 2

Given:

3 horses cost is equal to 5 cows cost. 4 horses, 6 cows total cost is 1900/-

To find:

The cost of each horse.

Solution:

Let the cost of one horse and one cow be x/- and y/- respectively.

So,

the cost of 3 horses = 3x/-

the cost of 4 horses = 4x/-

and

the cost of 5 cows = 5y/-

the cost of 6 cows = 6y/-

Now,

according to the question,

$3x = 5y \: \: (i)$

and

$4x + 6y = 1900 \: \: (ii)$

from (i), we have,

$x = \frac{5y}{3} \: \: \: (iii)$

on putting the value of x in (ii), we get

$4( \frac{5y}{3} ) + 6y = 1900$

On taking 3 as LCM, we have

$\frac{20y + 18y}{3} = 1900$

On solving,

$38y = 5700$

$y = 150 /-$

On putting the value of y in (iii), we get

$x = \frac{5(150)}{3}$

$x = 250/-$

Hence, the cost of each horse is 250/-