3. ବିଜୁଗୁଣନ ପ୍ରଣାଳୀରେ ସମାଧାନ (i) 3x+3y-5= 0 x-3y-9= 0 (ii) 3x+4y= 10 2x-2y=2 22_1 (i) 6 (x#0, y# 0) X
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3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
_____________________
3x+4y=10
3x−3y=3
_____________________
7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x=
3
6
=2
Hence x=2,y=1.
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