Math, asked by snhardikbarik2003, 5 hours ago

3. ବିଜୁଗୁଣନ ପ୍ରଣାଳୀରେ ସମାଧାନ (i) 3x+3y-5= 0 x-3y-9= 0 (ii) 3x+4y= 10 2x-2y=2 22_1 (i) 6 (x#0, y# 0) X​

Answers

Answered by umalaiappan
0

Answer:

Answer

3x+4y=10 …………..(1)

2x−2y=2 (or) x−y=1 …………(2)

(1) ⇒(3x+4y=10)1

(2) ⇒(x−y=1)3

_____________________

3x+4y=10

3x−3y=3

_____________________

7y=7

∴y=1

Put y=1 in (1) we get 3x+4×1=10

3x=10−4=6

∴x=

3

6

=2

Hence x=2,y=1.

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