3. (i) 5y – 2[y – 3(y – 5)] = 6
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Answer:
5y-2 [y-3(y-5)] = 6
=> 5y-2 [y-3y+15] = 6
=> 5y-2 [-2y+15] = 6
=> 5y+4y-30 = 6
=> 9y-30 = 6
=> 9y = 6+30
=> 9y = 36
=> y = 36/9
=> y = 4
Ans = 4
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