Question

In A ABC, the medians AD, BE and CF intersect in G, then which of the following is correct.
3
(1) BE + CF >
2
BC
(II) 4(AD + BE +CF) > 3(AB + BC + CA)
(III) BE + CF > AD
(IV) BE + AD > CF
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Answer 1

Answer:

(ll) option 4(AD+BE + CF) >3(AB + BC + CA)

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