Question

(3+i)x +(1-2i)y-7i^3=0 then x and y =

Answer 1

Answer:

x=-1, y=3

Step-by-step explanation:

(3+I)x+(1-2i)y-7i^3=0

3x+x+y-2iy-7i=0

(3x+y) +I(-2y+x-7)=0

now equate the real part with 0

3x+y=0

y=-3x

now equate the imaginary part with zero

-2y+x-7=0

now substitute the value of your in the imaginary part

-2(-3x)+x-7=0

-7x=7

x=-1

x=-1,y=-3x