Question

3. If A=1123
A
= 142.31,8=1724| then find 33-2.4​

Answer 1

Answer:

A∣I. Thus comparing it with the above equation gives us ∣A∣=10

Now ∣adjA∣=∣A∣

n−1

where n is the order of the square matrix.

Here 'n' is 3, therefore, ∣adjA∣=∣A∣

3−1

=∣A∣

2

=10

2

=100.