Question

In the following figure, ABCD is a square
and its two diagonals intersect at 0. If area
of A OAB is 4 cm”, find the side of the square.​

Answer 1

Answer:

$area \: of \: square = s \times s \\ = {s}^{2} \\ 4 \div 2 = 2$

SIDE =2 CM

Answer 2

Answer:

2 cm is answer.......

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