Question

3. If a and B are the zeroes of quadratic
polynomial x2 + 3x - 4
find the value of a3+ B3​

Answer 1

Step-by-step explanation:

(a+b)^3=a3+b3+3ab(a+b)

a+b=-3

ab=-4

-27=a3+b3+3*-3*-4

-27=a3+b3+36

Answer 2

Step-by-step explanation:

alpha + beta = -b/a

alpha * beta = c/a

now equation. was

x^2 +3x-4

so a = 1 , b = 3 and c = -4

let alpha be a

beta be b

now a+b = -b/a =-3/1

a*b = -4/1

a^3+b^3= (a+b)^3-3ab(a+b)

(-3)^3-3(-4)(-3)

-27+36

= 9