Question

prove range of projectile will be maximum 45​

Answer 1

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

Answer 2

Explanation:

range is directly proportional to the horizontal component of the velocity

at 45 degree the horizontal velocity is u cos theta=u*1/2

at 45 degree the vertical component is usin theta =u*1/2. that's why the time of flight is also more.

range =vel.(hori.)×time of flight