3.If a stone is dropped from a cliff, what will be its speed after it has fallen 100m?
Consider acceleration= 10m/s2
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Answer:
45.27m/s approx
Explanation:
Given:-
•Distance(s)=100m
•Acceleration due to gravity(g)=9.8m/s²
•Initial velocity(u)=0
To find:-
•Speed of the stone when it has fallen 100m
Solution:-
By using the 3rd equation of motion,when u=0,we get:-
=>v²=2gs
=>v²=2×9.8×100
=>v²=1960
= > v = \sqrt{1960}=>v=
1960
=>v=44.27m/s(approx)
Thus,speed of the stone when it has fallen 100m is 44.27m/s.
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