Question

3. IF AB = 12 cm, BC = 16 cm and AB is perpendicular
to BC, then the radius of the circle passing through
the points A, B and C is : ​

Answer 1

Step-by-step explanation:

Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.

To find out- the radius of the circle passing through A,B & C=?

Solution- BC⊥AB i.e ∠ABC=90

and ΔABC is a right one with AC as hypotenuse. ∴AC= AB square2+BC square2 = root12square2 +16square2..cm=20cm. So the circle passing through A,B & C will have its diameter as AC.

∴ Its radius= 21×20cm=10cm.