Question

3.
If p = - 3, q = 0, r = 2, find the value of-
(a) p + 9 + P + 1
​

Answer 1

Answer:

a)p+9+p+1=-3+9+-3+1=10

Answer 2

Given

p=-3

q=0

r=2

To Find

2pq+2qr-4pr=?

SOLUTION

2pq+2qr-4pr=(2×3×0)+(3×0×2) -(4×-3×2)

= 0+0-(-24)

=+24

ANSWER

therefore 2pq+2qr-4pr=24

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