Question

3
If sin [50°-3/2 theta]
=cos (30 - 50°), find the value of
theta
and hence evaluate
tan theta sec theta sin theta -cot theta sin theta cos theta.​

Answer 1

Answer:

sin(50°-3/2a) =cos(3a-50°)

sin(50°-3/2a) =sin{90°-(3a-50°) }

50°-3/2a=90°-3a+50°