Question

3. If x + 2y + 3z = 14,
2x + 3y + z = 11 and
3x + y + 2z = 11,
find (x + y + z).​

Answer 1

Answer:

answer

Step-by-step explanation:

let x+2y+3z=14

3x+y+2z=11

2x+3y+z=11

multiplying eqn (2) by 2 and subtracting eqn( 1) from it

we

get =5x+z=8

again multiplying eqn (2) by 3 and subtracting eqn (3) from it

we get =7x+5z=22

now multiply eqn (4) by 5 and subtract eqn (5) from it

we get 18x=18

:.x=1

substituting the x in eqn (4)

we get the value of z as =5(1)+z=8

:.z=8-5=3

and substitute x and z in eqn (1)

we get 1+2y+3(3)=14

2y=14-1-9=4

:.y=2

Answer 2

Answer:

x + 2y + 3z = 14,

2x + 3y + z = 11

and

3x + y + 2z = 11

then

X + Y + Z = 6