Math, asked by ds1234333, 1 month ago

3. If x = 3 is a root of bx² + bx + 6 = 0, find the value of b.​

Answers

Answered by ananyakumar2412
1

Answer:

b = -1/2

Step-by-step explanation:

if x=3 then:

3²(b) + 3b + 6=0

9b + 3b = -6

12b = -6

b = -6/12

therefore b = -1/2

Answered by Ashacecr7
0

Step-by-step explanation:

b(3)^2 +b(3) +6 =0

9b+3b+6=0

12b=-6

b=-1/2

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