Question

3 If (x-a) is a factor of 3ax -12 =0 ,then what is the value of a ? *​

Answer 1

Step-by-step explanation:

put x=a

3a^2-12=0

a^2=4

a=+-2

ans.

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Answer 2

Answer

Given :-

(x - a) is factor of p(x) = 3ax - 12 = 0

To find :-

Value of a

Solution :-

By using factor theorem -

$\sf x - a = 0$

$\sf x = a$

Substituting the value of x in p(x)

⟹ $\sf p(x) = 3ax - 12 = 0$

⟹ $\sf 3a(a) - 12 = 0$

⟹ $\sf 3a^2 - 12 = 0$

⟹ $\sf 3a^2 = 12$

⟹ $\sf a^2 = \frac{\cancel 12}{\cancel 3}$

⟹ $\sf a^2 = 4$

⟹ $\sf a = \sqrt{4}$

⟹ $\boxed{\sf a = 2 }$