Area of a rectangle is 51.2 dm² and the sides are in the ratio 5: 4.find it's perimeter.
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Answer:
Perimeter of rectangle = 96/√5 dm
Step-by-step explanation:
As the sides of the rectangle are in the ratio 5:4, we can denote them as:
5x and 4x.
ATQ, Area of the rectangle = 51.2 dm²
=> 5x*4x = 51.2
=> 9x² = 51.2
=> x² = 51.2/9
=> x² = 512/90
= 2*256/(9*10)
= (2/10)*(256/9)
= (1/5)*(256/9)
=> x = (1/√5)*(16/3)
=> x = 16/3√5
Perimeter of the rectangle = 2*5x + 2*4x
= 10x + 8x = 18x
=> Perimeter = 18*(16/3√5) = 96/√5
Perimeter of rectangle = 96/√5 dm
This is approximately equal to 43 dm
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