Question

3. In a circle with radius 14cm, an arc subtends
a right angle at the centre. Find the length
of this arc and the area of minor sector
and minor segment formed by it.​

Answer 1

Answer:

Given radius(r)=14cm

⇒ Area of sector OABO=

360

o

θ

πr

2

∴ Area of sector OABO=

360

o

90

o

×

7

22

×(14)

2

=154cm

2

⇒ Area of right angled △OAB=

2

1

×14×14=98cm

2

∴ Area of the minor segment of the circle = Area of sector OABO - Area of righta angled △ABO

∴ Area of the minor segment of the circle =(154−98)cm

2

=56cm

2

⇒ Area of circle =πr

2

=

7

22

×14×14=616cm

2

⇒ Area of the major segment of the circle = Area of circle - Area of minor segment.

∴ Area of the major segment of the circle =(616−56)cm

2

=560cm

2

Step-by-step explanation:

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