Question

3. In a quiz team. A.lcomed -40,10,0 and tlam B scored 10,0,- youn three wuccessive crounds. drich iteam emreld horl. con Widay that any order?​

Answer 1

answer

Given :

Length of the park is 60 m .

Perimeter of the path is 180 m .

To Find :

Breadth and Area of the park .

Solution :

\longmapsto\tt{Length=60\:m}⟼Length=60m

Using Formula :

\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}⟼

PerimeterofRectangle=2(l+b)

Putting Values :

\longmapsto\tt{180=2(60+b)}⟼180=2(60+b)

\longmapsto\tt{\cancel\dfrac{180}{2}=60+b}⟼

2

180

=60+b

\longmapsto\tt{90-60=b}⟼90−60=b

\longmapsto\tt\bf{30=b}⟼30=b

Now ,

For Area :

\longmapsto\tt{Length=60\:m}⟼Length=60m

\longmapsto\tt{Breadth=30\:m}⟼Breadth=30m

Using Formula :

\longmapsto\tt\boxed{Area\:of\:Rectangle=l\times{b}}⟼

AreaofRectangle=l×b

Putting Values :

\longmapsto\tt{60\times{30}}⟼60×30

\longmapsto\tt\bf{1800\:{m}^{2}}⟼1800m

2

So , The Area of the Rectangle is 1800 m² .