The sum of 'n' natural (positive integer) numbers is n-k. Find the maximum value of k', assuming that it is a whole number.
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Given : sum of 'n' natural (positive integer) numbers is
To find : maximum value of k',
Solution:
Sum on n natural positive numbers
1 + 2 + 3 + ...........................+ n
= n(n + 1)/2
= n!/2!(n-2)!
= ⁿC₂
Comparing with
k = 2
Value of k is 2
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