Question

3. In a rhombos PQRS if PQ = 7.5cm then find
the remaining sides If QPS= 75° then find
/PQR​

Answer 1

Step-by-step explanation:

In a rhombos PQRS if PQ = 7.5cm

in a rhombus all sides are equal.

then the remaining sides QR=RS=SP=PQ7.5Ccm

If QPS= 75° then

/PQR+QPS=180°[ sum of two adjacent angles=180° ]

/PQR+75°=180°

/PQR= 180°-75°

/PQR= 105°