Question

3.In ΔABC, if ∠A +∠B=108° and ∠B+∠C=130°,find ∠A, ∠B and∠C​

Answer 1

Answer:

According to your question

In a ABC triangle. A + B = 108 and B + C = 130

then find A B C

We know that according to angle sum property of triangle sum of all 3 sides are equal to 180°....

If A + B = 108°

then B = 108 - A ...... -(equation 1)

and B + C = 130

So , C = 130 - B ........ -(equation 2)

Now , A + B + C = 180

A + 108 - A + 130 - B = 180 (From Equ 1 and 2)

A will be cancelled from +A and -A

so, 238 - B = 180

= -B = 180 - 238

= -B = -58

minus (-) will be cancelled from both sides

so , B = 58°

and A + B = 108

and A + 58 = 108

A = 108 - 58 = 50°

so , A = 50°

and B + C = 130

58 + C = 130

C = 130 - 58

C = 72°

so we get the value that is

A = 50° , B = 58° and C = 72°

Answer 2

Answer:

Step-by-step explanation:

A+B+C=180

A=180-130=50

B=108-50=58

C=180-108=72