3. In Fig. 10.107, if AB | CD and CD I EF, find ZACE.
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Solution : Solution:
Given: CD || EF
∠ FEC + ∠ECD = 180°
[Sum of co-interior angles is supplementary to each other]
=> ∠ECD = 180° – 130° = 50°
Also, BA || CD
=> ∠BAC = ∠ACD = 70°
[Alternative angles of parallel lines are equal]
But, ∠ACE + ∠ECD =70°
=> ∠ACE = 70° — 50° = 20°
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