Question

3. In Fig. 6.15, PQR = PRQ, then prove that
PQS = PRT.​

Answer 1

Answer:

thus proved that they are equal

Answer 2

Answer with step-by-step-explanation:

Since rays QP and RP stand on ST.

Hence, ∠SQP + ∠PQR = 180° and ∠SRP + ∠PRT = 180°

=> ∠PQS + ∠PQR = 180° and ∠PRQ + ∠PRT = 180°

=> ∠PQS + ∠PQR = ∠PRQ + ∠PRT

=> ∠PQS + ∠PQR = ∠PQR + ∠PRT ________[Since, ∠PRQ = ∠PQR (Given)]

=> ∠PQS = ∠PRT

( Refer to the attachment )