Question

3. In figure, CD || AE and CY || BA.
(i) Name a triangle equal in area of ACBX.
(ii) Prove that ar(AZDE)=ar(ACZA).
(iii) Prove that ar(BCZY)=ar(AEDZ).​

Answer 1

Answer:

Step-by-step explanation:

Given In figure, CD||AE

and CY || BA

To prove ar (ΔCBX) = ar (ΔAXY) .

Proof We know that, triangles on the same base and between the same parallels are equal . in areas.

Here, ΔABY and ΔABC both lie on the same base AB and between the same parallels CY and BA.

ar (ΔABY) = ar (ΔABC)

⇒ ar (ABX) + ar (AXY) = ar (ABX) + ar (CBX)

⇒ ar (AXY) = ar (CBX) [eliminating ar (ABX) from both sides]