Question

3. In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how mu
red pigment should we mix with 1800 mL of base?
A menhinn inn oft drink factors fills 840 bottles in​

Answer 1

Answer:

24 parts of red pigments should be mixed with 1800 mL of base.

Step-by-step explanation:

Let the parts of red pigment required to mix with 1800 mL of base be x.

The given information in the form of a table is as follows.

Parts of red pigment                                         1                              x

Parts of base (in mL)                                        75                          1800

The parts of red pigment and the parts of base are in direct proportion. Therefore, we obtain

$\frac{1}{75} =\frac{x}{1800}$

$x=\frac{1 X1800}{75}$

x=24

Thus, 24 parts of red pigments should be mixed with 1800 mL of base.