Question

3. In the adjoining figure, lines AB and
CD intersect at F. If angleEFA = angleAFD and
angleCFB = 50°, find angleEFC.
50°,find angle EFC.​

Answer 1

Angle EFC is equal to 80°

Step-by-step explanation:

=> Angle AFD = 50° .....( vertically opposite angles )

=> Angle EFA = Angle AFD = 50 ° .......( given )

=> Angle EFA + Angle EFC + Angle CFB =

180°....... ( straight angle )

=> 50° + Angle EFC + 50° = 180°

=> Angle EFC + 100° = 180°

=> Angle EFC = 180° - 100°

=> Angle EFC = 80°

Therefore,

Angle EFC is equal to 80°