Question

3. In the adjoining figure PQ|| RS find xand y.​

Answer 1

angle X = 25 ( because alternative angles are equal)

add 65+30+z = 180 ( linear pair)

95+z= 180

z = 180-95

z= 85

now add angle x,y,z= x+y+z= 180( sum of the angle's in a triangle)

X= 25

Y= ?

Z = 85

25+y+85 = 180

110+ y = 180

y= 180-110

y= 70

angle x= 25°

angle y= 70°

hope it helps

                                                       OR

l (PQ) || l RQ

25+y = 65°_ (corresponding angles)

y=65-25=40°

now, z=180-(30+65)= 85°_linear pair angles .

now,

x+ y+z=180_ angle sum property of a triangle

therefore,

x=180-(z+y)=180-(85+40)=55°

x=55°

y=40°

Thanks

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Answer 2

first we find angle y.

180-25=55

so,angle y=55degree

now we find angle x.

180-30=150

so now we take out x by 180degree property

360=55+150+x

360=205+x

x=360-205

finally x=155degree