Question

3. In the given AP series the term at position 11 would be? 5, 8, 11, 14, 17, 20.........50. a) 35 b) 45 c) 25 d) None of the mentioned

Answer 1

ans is 35

step by step ans is given in pic

Answer 2

Answer:

Option (a) 35

Step-by-step explanation:

The given arithmetic progression series is 5, 8, 11, 14, 17, .... 50

Let the first term of the series be a = 5

Let the common difference of the series be d = 3

The $n^{th}$ term of the airthematic progression is given by a + (n-1)d

For the given series a= 5, d = 3

To find 11th term of given series consider,

$a_{n} =a+(n-1)d$

$a_{11}= a + 10d$

     = 5 + 30

$a_{11} = 35$

The 11th term of the series is 35.