3. In the given figure, O is the centre of the
circle. If angle PBC = 25° and angle APB = 110°, find
the value of angle ADB.
Answers
Answer:
85 degree
Step-by-step explanation:
In △ PCB
Using the angle sum property ∠PCB + ∠BPC + ∠PBC = 180 degree
We know that ∠APB and ∠BPC are linear pair
By substituting the values ∠PCB + (180 – 110) + 25 = 180
On further calculation ∠PCB + 70 + 25 = 180 ∠PCB + 95 = 180
By subtraction ∠PCB = 180 – 95 So we get ∠PCB = 85 We know that the angles in the same segment of a circle are equal
∠ADB = ∠ACB = 85
Therefore, the value of ∠ADB is 85 degree .
Answer:
85 degree
Step-by-step explanation:
In △ PCB
Using the angle sum property ∠PCB + ∠BPC + ∠PBC = 180 degree
We know that ∠APB and ∠BPC are linear pair
By substituting the values ∠PCB + (180 – 110) + 25 = 180
On further calculation ∠PCB + 70 + 25 = 180 ∠PCB + 95 = 180
By subtraction ∠PCB = 180 – 95 So we get ∠PCB = 85 We know that the angles in the same segment of a circle are equal
∠ADB = ∠ACB = 85
Therefore, the value of ∠ADB is 85 degree
