3 In the given quadrilateral ABCD show that <A=<C.
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given,
CD = AB
angle CDB = angle ABD -------eq 1
(taking tranasversal as BD)
therefore, CD || BA because of eq 1
then, quad ABCD = parallelogram
(quad with opposite sides equal and parallel is known as parallelogram)
angle A = angle C
(opposite sides of a parallelogram are equal)
but this question should be in maths section
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