Question

prove that tan+1/tanA= sec square A​

Answer 1

Answer:

1+tanAtan(A/2)=1+2tan(A/2)/1-tan^2(A/2)*tan(A/2)=1+2tan^2(A/2)/1-tan^2(A/2)=1+tan^2(A/2)/1-tan ^2(A/2)==1/cosA=secA