-3 is a zero of x²+x-6..
State whether it is true or false with reason
And
If x+2 and x-2 are the factors of ax⁴+2x-3x²+bx-4 then the value of a+b is
Plss give answer immediately
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Answer:
1) Yes
2) -1
Step-by-step explanation:
1) Applying remainder theorem:
f(x) = x²+x-6
f(-3) = (-3)² + (-3) - 6
f(-3) = 9 - 9 = 0
2)
x-2 = 0 {x = 2}
f(x) = ax⁴+2x-3x²+bx-4
f(2) = 16a+4-12+2b-4
0 = 16a+2b-12
6=8a+b --------------------- 1
x+2 = 0 {x = -2}
f(x) = ax⁴+2x-3x²+bx-4
f(-2) = 16a-4-12-2b-4
0 = 16a-2b-20
10=8a-b --------------------- 2
Adding 1 and 2:
8a+b+8a-b = 6+10
16a = 16 --------------------- a=1
b=6-8a
b=6-8 --------------------- b=(-2)
Hence a+b = -1
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