Physics, asked by arorabhumi3922, 19 hours ago

A ball weighing 1kg has a velocity of 4m/s after falling through a vertical distance of 1m. How much energy is lost to the atmosphere? (Take g = 10 m/s^2)

Answers

Answered by Sayantana
3

Concept:

  • Any object at some height above the earth's surface will have some potential energy due to gravitational field.
  • and this type of conservative force get change into Kinetic energy whenever any loss, gain happens.
  • Together they known as mechanical energy.

But due to resistive forces present in atmosphere some of energy get lost in the form of heat.

Solution:

According to attached image, the motion of the ball is from A to B.

At "A"

  • Energy = potential energy = U
  • U = mgh = 1 × 10 × 1 = 10J

At "B"

  • Energy = kinetic energy = K
  • K = ½ mv² = ½ × 1 × (4)² = ½ × 1×4 ×4
  • K = 2 × 4 = 8J

Energy lost = initial energy - final energy

  • U - K = 10J - 8J = 2J

☆so, 2J of energy is lost to the atmosphere.

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