Question

3 is one of the zeros of polynomial p(x)=
$x {3} + 3x {2} + kx + 24$
then k=_​

Answer 1

$\underline{\bigstar{\sf\ Given:-}}$

• 3 is the zero of the polynomial x³ + 3x² + kx + 24

$\underline{\bigstar{\sf\ To\:Find:-}}$

• Value of k

$\underline{\bigstar{\sf\ Solution:-}}$

Put x = 3 in the given polynomial :

⇒ p (3) = (3)³ + 3(3)² + k(3) + 24 = 0

⇒ 27 + 27 + 3k + 24 = 0

⇒ 78 + 3k = 0

⇒ 3k = - 78

$⇒ \: k = \frac{ - 78}{3}$

$⇒ \: k \: = - 26$

PLEASE MARK IT BRAINILIEST

Answer 2

Answer:

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