(3) Is the sum of the angles of any polygon 1600°? How about 900°?
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Answer:
The sum the angles of any polygon is (n-2)*180°
Where n is no of vertices.
1600=(n-2)*180
1600/180=(n-1)
80/9=(n-1)
n=80/9+1
n=89/1
THEREFORE IT IS NOT POSSIBLE.
900=(n-2)*180
900/180=n-2
5=n-2
n=7
THEREFORE IT IS POSSIBLE.
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