3. Joe purchased 20 apples from a supermarket for 180 rupees at a discount of 10 percent. How
mhich will e dozen apples cost him if he does not avail any diecount?
Answers
Answer:
Rs. 120
Step-by-step explanation:
Let the original price without discount for the 20 apples be Rs.x
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 180
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200The price of 20 apples = Rs. 200
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200The price of 20 apples = Rs. 200So, the price of 1 apple = 200/20 = Rs. 10
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200The price of 20 apples = Rs. 200So, the price of 1 apple = 200/20 = Rs. 10Price of a dozen apples(1 dozen = 12 apples)
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200The price of 20 apples = Rs. 200So, the price of 1 apple = 200/20 = Rs. 10Price of a dozen apples(1 dozen = 12 apples) = Rs. (10×12)
Let the original price without discount for the 20 apples be Rs.xx - 10% of x = Rs. 180x - 10/100 × x = 180x - 1/10 × x = 180(10x - 1x )/ 10 = 1809x/10 = 180x = ( 180 × 10 )/ 9x = 20 × 10x x = 200The price of 20 apples = Rs. 200So, the price of 1 apple = 200/20 = Rs. 10Price of a dozen apples(1 dozen = 12 apples) = Rs. (10×12) = Rs. 120
HOPE IT WOULD HELP YOU
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ALVIKA RAJ
Answer:
₹120
Step-by-step explanation:
Let the original price of the 20 apples be x.
According to the problem,
90% of x = ₹180. (As 10% was discount)
90/100 * x = 180 (cut off the zeroes)
9/10 * x = 180
9x/10 = 180
9x = 180 * 10
9x = 1800
x = 1800/9 = ₹200.
Therefore, 1 apple = ₹10 (Unitary method)
Therefore, dozen ( = 12) = ₹10 * 12 = 120
Answer is ₹120