3
John had some pencils. of them
5
were red and the rest were green. He
2
1
gave of the red pencils and of
3
4
the green pencils to his sister. If he
had 80 pencils left, how many pencils
did he have at first?
Answers
Answered by
2
Answer:
red = 3x/5
green= (x-3x/5)=2x/5
red pencil given to sister = 2/3*3x/5 = 2x/5
red pencil left = 3x/5-2x/5 = x/5
green pencil given to sister = 1/4*2x/5 = x/10
green pencil left= 2x/5-x/10 =3x/10
total pencil left = x/5 + 3x/10 = x/2
A/C, x/2=80
x= 160.
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