Physics, asked by hardikbaraiya014, 7 months ago

3 kg of water at 283 K is brought into contact with a heat reservoir at 363 K. When the water has reached 363 K, find the entropy change of water, of reservoir and of universe.

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Answered by Anonymous

Answer:

Calculate the change in entropy of the water as it freezes completely and slowly ... latent heat of fusion for water/ice = 333000 J/kg ... ΔStea = ∫ 363K293 mcdT/T = mc ln(293/363) = -0.2 kg * 1100 cal/(kg K) ...

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3 kg of water at 283 K is brought into contact with a heat reservoir at 363 K. When the water has reached 363 K, find the entropy change of water, of reservoir and of universe.​

Answers

3 kg of water at 283 K is brought into contact with a heat reservoir at 363 K. When the water has reached 363 K, find the entropy change of water, of reservoir and of universe.