Math, asked by muskanchalotra381, 4 months ago

3. Length of the fence of
a trapezium shaped field
ABCD is 120 m. If BC = 48 m,
CD = 17 m and AD = 40 m, find
the area of this
field. Side AB
is perpendicular to the
parallel sides AD and BC.​

Answers

Answered by XxitsmrseenuxX
6

Answer:

660m^2

Step-by-step explanation:

Mensuration:

Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.

Plane Figure: A figure which lies in a plane is called a plane figure.

For e.g:  a rectangle, square, a rhombus, a parallelogram, a trapezium.

Perimeter:

The perimeter of a closed plane figure is the total length of its boundary.

In case of a triangle or a polygon the perimeter is  the sum of the length of its sides.

Unit of perimeter is a centimetre  (cm), metre(m) kilometre(km) e.t.c

Area: The area of the plane figure is the measure of the surface enclose by its boundary.

The area of a triangle are a polygon is the measure of the surface enclosed by its sides.

A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.

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Solution;

Given:

Length of the fence of a trapezium ABCD =120 m.  BC = 48 m, CD = 17 m and AD = 40 m,

Length of the fence of a trapezium ABCD =AB +BC+ CD+ AD

120=AB + 48+17+40

120 = AB + 105

120 – 105 = AB

AB= 15 m

Height (AB) = 15 m

Area of Trapezium

= 1/2 x sum of parallel sides x perpendicular distance

Area of Trapezium

= (1/2) (48+40) 15

= ½(88)(15)

= 44× 15

=660 m²

Hence, the area of the field = 660 m²

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Hope this will help you...

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