Question

3 log 1.5+ log 240 - 2 log 9

Answer 1

I've used basic logarithmic formulas to solve this.....

Answer 2

Step-by-step explanation:

3 log 1.5 can be written as=3 log 3/2

log 240 can be written as

log 2×120=2×60×2=2×2×2×2×3×5

=log(2⁴×3×5)

2log9 can written as=2log(3²)

Now We know Some laws of Logarithm.

log (a× b)=log a +log b

log(a/b)=log a- log b

log a^b=b log a

Using this. Write All the terms given above.

3log3/2+log(2⁴×3×5)+2log3²

3[log3-log2]+log2⁴+log3+log5-2×2log3

3[log3-log2]+4log2+log3+log5-4log3

3log3-3log2+4log2+log3+log5-4log3

3log3-4log3+log3-3log2+4log2+log5

log3(3-4+1)+log2(3-2)+log5

log2+log5

log(2×5)

log10

log of base 10=1

Answer=1