[3^m^2 /(3^m)^2]^1/2=81
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Given If [3^m² ÷ (3^m)² ]^1/m = 81 , then find the value of m.
We need to find the value of m. By using law of exponents a^m / a^n = a^m-n and (a^m)^n = a^mn
So we have
[3^m^2 / (3^m)^2]^1/m = 81
3^m / 3^2 = 81 by using (a^m)^n = a^mn
3^m – 2 = 3^4
m – 2 = 4
m = 4 + 2
m = 6
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