Question

3(m-4)/15- (m-5)/10= 2(3-m)/5
Find the value of m.

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given,

$\frac{3(m-4)}{15}- \frac{(m-5)}{10}= \frac{ 2(3-m)}{5}$

Here we have to find the value of $m$

First move all the terms to LHS.

$\frac{3(m-4)}{15}- \frac{(m-5)}{10}- \frac{ 2(3-m)}{5}=0$

Cancel the similar terms to make it simple.

$\frac{(m-4)}{5}- \frac{(m-5)}{10}-\frac{ 2(3-m)}{5}=0$

$\frac{(m-4)}{5}-\frac{ 2(3-m)}{5}- \frac{(m-5)}{10}=0$

$\frac{(m-4)}{5}-\frac{ 6-2m}{5}- \frac{(m-5)}{10}=0$

$\frac{m-4-6+2m}{5}- \frac{(m-5)}{10}=0$

$\frac{3m-10}{5}- \frac{(m-5)}{10}=0$

To make the denominators same, we have to do LCM

We get,

$\frac{6m-20- m+5}{10}=0$

$\frac{5m-15}{10}=0$

The number $10$ in the denominator moves to RHS it becomes zero.

$5m-15=0$

Take $5$  common from the above equation.

We get,

$m-3=0$

$m=3$

Therefore, the value of $m$ is $3$